How do you solve $12x-4=32$ ?

Question

4197 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-14T18:33:55

$x=3$

First, add four to both sides which will leave you with

$12x=36$

Next, divide by $12$ on both sides leaving you with

$x=3$

Answer 2 · 2017-06-14T18:34:53

See a solution process below:

Step 1) Add $color(red)(4)$ to each side of the equation to isolate the $x$ term while keeping the equation balanced:

$12x - 4 + color(red)(4) = 32 + color(red)(4)$

$12x - 0 = 36$

$12x = 36$

Step 2) Divide each side of the equation by $color(red)(12)$ to solve for $x$ while keeping the equation balanced:

$(12x)/color(red)(12) = 36/color(red)(12)$

$(color(red)(cancel(color(black)(12)))x)/cancel(color(red)(12)) = 3$

$x = 3$

How do you solve 12x-4=3212x-4=32?