How do you solve $\frac{15 - a}{3} = - 9$ $(15-a)/3=-9$ ?

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Answer 1 · 2016-12-24T16:00:18

$\frac{15 - a}{3} = - 9$ $(15-a)/3=-9$

or, $\frac{15 - a}{3} * 3 = - 9 \cdot 3$ $(15-a)/3**3=-9*3$

or, $15 - a = - 27$ $15-a=-27$

or, $15 - 15 - a = - 27 - 15$ $15-15-a=-27-15$

or, $- a = - 42$ $-a=-42$

or, $cancel(-)a=cancel(-)42$

or, $a=42$

How do you solve (15-a)/3=-915−a3=−9(15-a)/3=-9?