How do you solve $15x + 12y = -12$ and $5x + 4y = -4$ ?

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Answer 1 · 2017-05-21T13:33:57

There are infinite solutions. They are all the points on the line $5x+4y=-4$ .

Divide the first equation by 3.

$15/3x+12/3y=-12/3$

$5x+4y=-4$

Therefore, the two lines are the same. This means the solution set is the line $5x+4y=-4$ .

How do you solve 15x + 12y = -1215x + 12y = -12 and 5x + 4y = -45x + 4y = -4?