How do you solve #2.2x-6/4=-7#?

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Answer 1 · 2015-03-25T18:29:39

Starting with
#2.2x - 6/4 = -7#

Multiply both sides by #4# to get rid to the fraction
#8.8x - 6 = -28#

Add #6# to both sides
#8.8x = -22#

Divide both sides by #8.8#
#x = - (22)/(8.8) = -2.5#

Answer 2 · 2015-03-25T18:30:55

The answer is: #x=-5/2#.

#22/10x=-7+3/2rArr11/5x=(-14+3)/2rArr#

#x=5/11*(-11/2)rArrx=-5/2#.