How do you solve $\frac{2}{3} = 2 - \frac{5 x - 3}{x - 1}$ $2/3 = 2 - (5x-3)/(x-1)$ ?

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Answer 1 · 2016-06-19T20:39:37

$x = \frac{5}{11}$ $x=5/11$ .

$\frac{2}{3} = 2 - \frac{5 x - 3}{x - 1}$ $2/3=2-(5x-3)/(x-1)$

$\frac{2}{3} - 2 = - \frac{5 x - 3}{x - 1}$ $2/3-2=-(5x-3)/(x-1)$

$- \frac{4}{3} = - \frac{5 x - 3}{x - 1}$ $-4/3=-(5x-3)/(x-1)$

$\frac{4}{3} = \frac{5 x - 3}{x - 1}$ $4/3=(5x-3)/(x-1)$

$\frac{4}{3} (x - 1) = 5 x - 3$ $4/3(x-1)=5x-3$

$4 (x - 1) = 3 (5 x - 3)$ $4(x-1)=3(5x-3)$

$4 x - 4 = 15 x - 9$ $4x-4=15x-9$

$4 x - 15 x = - 9 + 4$ $4x-15x=-9+4$

$- 11 x = - 5$ $-11x=-5$

$x = \frac{5}{11}$ $x=5/11$ .

How do you solve 23=2−5x−3x−12/3 = 2 - (5x-3)/(x-1)?