How do you solve $2 + (3/(x-1)) = 10$ ?

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Answer 1 · 2016-03-10T02:39:39

You must start by putting on an equal denominator.

The LCD (least common denominator) is $x - 1$

$(2(x - 1))/(x - 1) + 3/(x - 1) = (10(x - 1))/(x - 1)$

We can now eliminate the denominators and solve.

$2x - 2 + 3 = 10x - 10$

$11 = 8x$

$11/8 = x$

Practice exercises:

$(2)/(2x + 3) + 3/(x - 1) = 5/(x - 1)$

Challenge problem:

Solve for x: $1/x + 1/(xy) = 2/(y + x)$

Good luck!

How do you solve 2 + (3/(x-1)) = 102 + (3/(x-1)) = 10?