How do you solve $2=(5p-7)/4$ ?

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Answer 1 · 2016-07-12T00:28:17

p=3

Multiply 4 on both sides to get rid of the denominator:

$4xx2=(5p-7)/cancel4$ $xxcancel4$

Add 7 to both sides to get the constant by itself:

$8 = 5p-7$
$+7 color(white)(aaa) +7$

$15=5p$

Divide both sides by 5 to find p:
$15/5=(cancel5p)/cancel5$

$3=p$

How do you solve 2=(5p-7)/42=(5p-7)/4?