How do you solve $\frac{2}{k} - \frac{3}{k} + 4 = \frac{3}{k}$ $2/k-3/k+4=3/k$ ?

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How do you solve $\frac{2}{k} - \frac{3}{k} + 4 = \frac{3}{k}$ $2/k-3/k+4=3/k$ ?

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Answer 1 · 2018-05-02T19:21:09

k = 1

Explanation:

Multiply every term in the equation by k to get:
$2 - 3 + 4 k = 3$ $2 - 3 + 4k = 3$
Solve for k.
$4 k = 3 - 2 + 3$ $4k = 3 - 2 + 3$
$4 k = 4$ $4k = 4$
$k = 1$ $k = 1$

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How do you solve $\frac{2}{k} - \frac{3}{k} + 4 = \frac{3}{k}$ $2/k-3/k+4=3/k$ ?

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How do you solve $\frac{2}{k} - \frac{3}{k} + 4 = \frac{3}{k}$ $2/k-3/k+4=3/k$ ?