How do you solve $2 (\sqrt{x}) + \frac{5}{6} = \frac{13}{6}$ $2(sqrt x) + 5/6 = 13/6$ ?

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Answer 1 · 2015-07-27T17:51:27

You first put all numbers to one side

Subtract $\frac{5}{6}$ $5/6$ on both sides:
$\to 2 \sqrt{x} = \frac{8}{6} = \frac{4}{3}$ $->2sqrtx=8/6=4/3$

Now divide both sides by $2$ $2$ :
$\to \sqrt{x} = \frac{2}{3}$ $->sqrtx=2/3$

Then, square both sides:
$\to {\sqrt{x}}^{2} = x = {(\frac{2}{3})}^{2} = \frac{2^{2}}{3^{2}} = \frac{4}{9}$ $->sqrtx^2=x=(2/3)^2=2^2/3^2=4/9$

$\to x = \frac{4}{9}$ $->x=4/9$

How do you solve 2(sqrt x) + 5/6 = 13/62(√x)+56=1362(sqrt x) + 5/6 = 13/6?