How do you solve $2/(x+1) + 5/(x-2)=-2$ ?

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Answer 1 · 2017-02-07T08:02:22

$x=1/2 and -3$

$2/(x+1) + 5/(x-2) = -2$

multiply with $(x+1)(x-2)$ to both side.

$2(x-2) + 5(x+1) = -2(x+1)(x-2)$

$2 x-4+5 x+5=-2(x^2-x-2)$

$7x+1=-2x^2+2x+4$

move to one side.
$2x^2+5x-3=0$

$(2x-1)(x+3)=0$

$x=1/2 and -3$

How do you solve 2/(x+1) + 5/(x-2)=-22/(x+1) + 5/(x-2)=-2?