How do you solve #2/(x+1) + 5/(x-2)=-2#?

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Answer 1 · 2017-02-07T08:02:22

#x=1/2 and -3#

#2/(x+1) + 5/(x-2) = -2#

multiply with #(x+1)(x-2)# to both side.

#2(x-2) + 5(x+1) = -2(x+1)(x-2)#

#2 x-4+5 x+5=-2(x^2-x-2)#

#7x+1=-2x^2+2x+4#

move to one side.
#2x^2+5x-3=0#

#(2x-1)(x+3)=0#

#x=1/2 and -3#