How do you solve $2/(x+1) + 5/(x-2)=-2$ ?

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Answer 1 · 2017-10-29T10:43:11

Solution: $x=1/2 and x=-3$

$2/(x+1)+5/(x-2) =-2$ . Multiplying by $(x+1)(x-2)$ on both

sides we get , $2(x-2)+5(x+1) =-2(x+1)(x-2)$ or

$2x-4+5x+5 = -2(x^2-x-2)$ or

$7x+1 = -2x^2+2x+4 or 2x^2+5x-3=0$ or

$2x^2+6x-x-3=0 or 2x(x+3)-1(x+3)=0$ or

$(x+3)(2x-1)=0$ . Either $x+3=0:.x=-3$ or

$2x-1=0 :. x= 1/2$

Solution: $x=1/2 and x=-3$ [Ans]

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