How do you solve $(-22+3x)/(3x+7)$ =2#?

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Answer 1 · 2016-11-28T02:07:28

$x = -12$

First, multiply each side of the equation by (3x + 7) to eliminate the fraction:

$((3x + 7)*(-22 + 3x))/(3x + 7) = 2(3x + 7)$

$(cancel(3x + 7)*(-22 + 3x))/cancel(3x + 7) = 6x + 14$

$-22 + 3x = 6x + 14$

You can now complete this problem using the necessary mathematics to isolate and solve for $x$ :

$-22 + 3x - 3x - 14 = 6x + 14 - 3x - 14$

$-22 - 14 = 6x - 3x$

$-36 = 3x$

$(-36)/3 = (3x)/3$

$-12 = x$

How do you solve (-22+3x)/(3x+7)(-22+3x)/(3x+7)=2#?