Question

How do you solve `2a^2-30a+108=0`?

Answer 1

Solve `f(x) = 2a^2 - 30a + 108 = 0`

Ans: 6 and 9

Explanation:

`f(x) = 2y = 2(a^2 - 15a + 54) = 0`
`y = a^2 - 15a + 54 = 0`
I use the new Transforming Method. Both roots are positive.
Factor pairs of (54) -> (2, 27)(3, 18)(6, 9). This sum is 15 = -b.
Then, the 2 real roots of y are : 6 and 9

NOTE. To know more about The new Transforming Method for solving quadratic equations, please search into Google, Yahoo or Bing.

Answer 2

Use the Bhaskara formula to find `x'=9` and `x''=6`.

Explanation:

The Bhaskara formula is: `x=(-b+-sqrt(b^2-4ac))/(2a)`, where a is the number that multiplies `x^2`, b is the number that multiplies `x` and c is the number that doesn't multiply anyone. You should get to the following calculation:
`x=(30+-6)/4`.
There will be two answers. x' is the sum and x'' is the subtraction.