How do you solve $- 2b + 9= 25$ ?

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Answer 1 · 2018-05-11T02:19:52

$b = -8$

$-2b + 9 = 25$

To solve for $color(blue)b$ , we have to make it by itself.

To do so, first subtract $color(blue)9$ from both sides of the equation:
$-2b + 9 quadcolor(blue)(-quad9) = 25 quadcolor(blue)(-quad9)$

$-2b = 16$

Now divide both sides by $color(blue)(-2)$ :
$(-2b)/color(blue)(-2) = 16/color(blue)(-2)$

$b = -8$

Hope this helps!

How do you solve - 2b + 9= 25- 2b + 9= 25?