How do you solve $2c+13=19$ ?

Question

2368 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-12T20:44:41

See a solution process below:

Step 1) Subtract $color(red)(13)$ from each side of the equation to isolate the $c$ term while keeping the equation balanced:

$2c + 13 - color(red)(13) = 19 - color(red)(13)$

$2c + 0 = 6$

$2c = 6$

Step 2) Divide each side of the equation by $color(red)(2)$ to solve for $c$ while keeping the equation balanced:

$(2c)/color(red)(2) = 6/color(red)(2)$

$(color(red)(cancel(color(black)(2)))c)/cancel(color(red)(2)) = 3$

$c = 3$

Answer 2 · 2017-06-12T20:47:35

$c=3$

We need to move all terms that don't contain $c$ to the right side and solve.

$2c + 13 = 19$

-subtract $13$ from each side

$2c cancel(+13 - 13) =19 -13$

$2c=6$

-divide each side by $2$

$c=3$

How do you solve 2c+13=192c+13=19?