How do you solve $-2m ^ { 2} - 6= 0$ ?

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Answer 1 · 2016-10-27T07:32:02

There are no real solutions.

$-2m^2 -6=0$

Although this is a quadratic $(m^2)$ we can use a different method to solve it because there is no $m$ term.

Write it as $" "2m^2 = -6" "larr$ solve for $m. div 2$

$m^2 = -3" "larr$ find the square root

$m = +-sqrt-3$

This is where we hit a problem, because you cannot find the square root of a negative value.

Therefore: there are no Real solutions for this equation

How do you solve -2m ^ { 2} - 6= 0-2m ^ { 2} - 6= 0?