Question

How do you solve `-2n+3=8`?

Answer 1

`n=-5/2`

Explanation:

Leave the n term and move numeric values to the right side of the equation.

subtract 3 from both sides.

`-2ncancel(+3)cancel(-3)=8-3`

`rArr-2n=5`

to solve for n divide both sides by -2.

`(cancel(-2) n)/cancel(-2)=5/(-2)`

`rArrn=-5/2`