How do you solve $- 2 \sqrt[5]{2 x - 1} + 4 = 0$ $-2root5(2x-1)+4=0$ ?

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Answer 1 · 2018-05-27T11:29:10

$x = \frac{33}{2}$ $x=33/2$

Writing
$- 2 {(2 x - 1)}^{\frac{1}{5}} = - 4$ $-2(2x-1)^(1/5)=-4$
Dividing by $- 2$ $-2$

${(2 x - 1)}^{\frac{1}{5}} = 2$ $(2x-1)^(1/5)=2$
Raising to the power $5$ $5$

$2 x - 1 = 32$ $2x-1=32$

$x = \frac{33}{2}$ $x=33/2$

How do you solve −25√2x−1+4=0-2root5(2x-1)+4=0?