How do you solve $2s - 3t = 13$ and $2s + 2t = -2$ ?

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Answer 1 · 2015-08-22T07:58:50

The solutions are
$color(blue)(s=2,t=-3$

$color(blue)(2s)−3t=13$ ....equation $1$
$color(blue)(2s)+2t=−2$ .....equation $2$

Solving by elimination

Subtracting equation $1$ from $2$

$cancelcolor(blue)(2s)−3t=13$
$cancelcolor(blue)(-2s)-2t=+2$

$-5t=15$
$color(blue)(t=-3$

Finding $s$ from equation $2$
$2s−3t=13$
$2s=13+3t$
$2s=13-9$
$color(blue)(s=2$

How do you solve 2s - 3t = 132s - 3t = 13 and 2s + 2t = -22s + 2t = -2?