How do you solve $2x+1=8$ ?

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Answer 1 · 2018-05-24T01:03:19

See a solution process below:

First, subtract $color(red)(1)$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$2x + 1 - color(red)(1) = 8 - color(red)(1)$

$2x + 0 = 7$

$2x = 7$

Now, divide each side of the equation by $color(red)(2)$ to solve for $x$ while keeping the equation balanced:

$(2x)/color(red)(2) = 7/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 7/2$

$x = 7/2$

Answer 2 · 2018-05-24T01:07:34

$x = 7/2$

The first step is to get $x$ by itself. You subtract the $1$ from both sides

$2x +1-1=8-1$

So now you only have

$2x=7$

You divide both sides by $2$ to get $x$ by itself.

$(2x)/2=7/2$

and you get your answer!

$x=3.5$

How do you solve 2x+1=82x+1=8?