How do you solve $-2x + 16\leq 35- 16$ ?

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Answer 1 · 2016-11-19T13:59:08

$x >= -3/2$

Perform the necessary mathematics to isolate and solve for $x$ while keeping the inequality balanced.

First, subtract 16 from each side of the inequality:

$-2x + 16 - 16 <= 35 - 16 - 16$

$-2x + 0 <= 35 - 32$

$-2x <= 3$

Next divide each side by $-2$ . Because we are multiplying or dividing by a negative number the inequality needs to be reversed:

$(-2x)/-2 >= 3/(-2)$

$1x >= -3/2$

$x >= -3/2$

How do you solve -2x + 16\leq 35- 16-2x + 16\leq 35- 16?