How do you solve $2 x^{2} - 11 x = 1$ $2x^2-11x=1$ using the quadratic formula?

Question

2304 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-09T08:27:37

$x = \frac{7 + \sqrt{129}}{4}, x = \frac{7 - \sqrt{129}}{4}$ $color(brown)(x = (7 + sqrt129) / 4, x = (7 - sqrt129) / 4$

$2 x^{2} - 11 x - 1 = 0$ $2x^2 - 11x - 1 = 0$

$a = 2, b = - 11, c = - 1$ $a = 2, b = -11, c = -1$

$Quadratic Formula x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $"Quadratic Formula " x = (-b +- sqrt(b^2 - 4ac)) / (2a)$

$x = \frac{11 \pm \sqrt{11^{2} + 8}}{4}$ $x = (11 +- sqrt(11^2 + 8)) / 4$

$x = \frac{7 + \sqrt{129}}{4}, x = \frac{7 - \sqrt{129}}{4}$ $x = (7 + sqrt129) / 4, x = (7 - sqrt129) / 4$

How do you solve 2x^2-11x=12x2−11x=12x^2-11x=1 using the quadratic formula?