How do you solve 2x^2 = 14x + 202x2=14x+20 using the quadratic formula?

1 Answer
ali ergin
Apr 23, 2016

x_1=-1,22x1=−1,22
x_2=8,22x2=8,22

Explanation:

2x^2=14x+202x2=14x+20
2x^2-14x-20=02x2−14x−20=0
2(x^2-7x-10)=02(x2−7x−10)=0
x^2-7x-10=0x2−7x−10=0

ax^2+bx+c=0ax2+bx+c=0
a=1" ; "b=-7" ; "c=-10a=1 ; b=−7 ; c=−10

Delta=sqrt(b^2-4*a*c)

Delta=sqrt(49+4*1*10)

Delta=sqrt89

Delta=9,43

x_1=(-b-Delta)/(2*a)

x_1=(7-9,43)/2

x_1=-1,22

x_2=(-b+Delta)/(2*a)

x_2=(7+9,43)/2

x_2=8,22

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