How do you solve $2 x^{2} = 16$ $2x^2 = 16$ ?

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Answer 1 · 2015-08-02T00:32:54

$x = 2 \sqrt{2}, - 2 \sqrt{2}$ $x=2sqrt2, -2sqrt 2$

$2 x^{2} = 16$ $2x^2=16$

Divide both sides of the equation by $2$ $2$ .

$x^{2} = \frac{16}{2}$ $x^2=16/2$ =

$x^{2} = 8$ $x^2=8$

Take the square root of both sides.

$x = \pm \sqrt{8}$ $x=+-sqrt8$

$x = \pm \sqrt{2 \times 2 \times 2}$ $x=+-sqrt(2xx2xx2)$

$x = \pm \sqrt{2^{2} \times 2}$ $x=+-sqrt(2^2xx2)$

Apply the rule $\sqrt{a^{2}} = a$ $sqrt (a^2)=a$ .

$x = \pm 2 \sqrt{2}$ $x=+-2sqrt2$

Solve for $x$ $x$ .

$x = 2 \sqrt{2}$ $x=2sqrt 2$

$x = - 2 \sqrt{2}$ $x=-2sqrt2$

How do you solve 2x2=162x^2 = 16?