How do you solve $2x^2= 5x-9$ using the quadratic formula?

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Answer 1 · 2016-02-29T22:26:42

$2x^2-5x+9=0$
$a = 2,b = -5, c = 9, x = (5+-sqrt (25-4*2*9))/4$
$x=(5+-sqrt(-47))/4= no solution$

First put all the terms on one side then determine the values of a, b, and c and then put it in to the quadratic formula and simplify.

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