How do you solve $- 2 x^{2} - 7 x = - 1.5$ $-2x^2-7x=-1.5$ using the quadratic formula?

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How do you solve $- 2 x^{2} - 7 x = - 1.5$ $-2x^2-7x=-1.5$ using the quadratic formula?

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Answer 1 · 2017-08-25T09:38:04

$x \approx - 3.7, x \approx 0.2$ $x~~ -3.7,x~~ 0.2$

Explanation:

$rearrange and equate to zero$ $"rearrange and equate to zero"$

$\Rightarrow - 2 x^{2} - 7 x + 1.5 = 0$ $rArr-2x^2-7x+1.5=0$

$with a = - 2, b = - 7, c = 1.5$ $"with "a=-2,b=-7,c=1.5$

$solving using the quadratic formula$ $"solving using the "color(blue)"quadratic formula"$

$for the quadratic a x^{2} + b x + c = 0$ $"for the quadratic "ax^2+bx+c=0$

$∙ x x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)$

$\Rightarrow x = \frac{7 \pm \sqrt{49 + 12}}{- 4}$ $rArrx=(7+-sqrt(49+12))/(-4)$

$\Rightarrow x = \frac{7 + \sqrt{61}}{- 4} or x = \frac{7 - \sqrt{61}}{- 4}$ $rArrx=(7+sqrt61)/(-4)" or "x=(7-sqrt61)/(-4)$

$\Rightarrow x \approx - 3.7 to 1 dec. place or x \approx 0.2 to 1 dec. place$ $rArrx~~ -3.7" to 1 dec. place or "x~~ 0.2" to 1 dec. place"$

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How do you solve $- 2 x^{2} - 7 x = - 1.5$ $-2x^2-7x=-1.5$ using the quadratic formula?

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How do you solve $- 2 x^{2} - 7 x = - 1.5$ $-2x^2-7x=-1.5$ using the quadratic formula?