How do you solve $2 x^{2} - 9 x + 7 = 0$ $2x^2 - 9x + 7 = 0$ ?

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How do you solve $2 x^{2} - 9 x + 7 = 0$ $2x^2 - 9x + 7 = 0$ ?

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Answer 1 · 2016-08-06T15:09:29

This equation has solutions $x = \frac{7}{2}$ $x=7/2$ and $x = 1$ $x=1$

Explanation:

Notice that $9 = 2 + 7$ $9 = 2+7$ .

So we find:

$0 = 2 x^{2} - 9 x + 7$ $0 = 2x^2-9x+7$

$= 2 x^{2} - 2 x - 7 x + 7$ $= 2x^2-2x-7x+7$

$= 2 x (x - 1) - 7 (x - 1)$ $= 2x(x-1)-7(x-1)$

$= (2 x - 7) (x - 1)$ $= (2x-7)(x-1)$

Hence zeros: $x = \frac{7}{2}$ $x=7/2$ and $x = 1$ $x=1$

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How do you solve $2 x^{2} - 9 x + 7 = 0$ $2x^2 - 9x + 7 = 0$ ?

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How do you solve $2 x^{2} - 9 x + 7 = 0$ $2x^2 - 9x + 7 = 0$ ?