How do you solve √(2x –3) = 2?

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Answer 1 · 2018-03-02T17:18:14

$\frac{7}{2}$ $7/2$

Square both sides:

${\sqrt{2 x - 3}}^{2} = 2^{2}$ $sqrt(2x-3)^2=2^2$

${\sqrt{2 x - 3}}^{2}$ $sqrt(2x-3)^2$ becomes $2 x - 3 .$ $2x-3.$ In general, ${\sqrt{x}}^{2} = x .$ $sqrt(x)^2=x.$ Squaring a root removes the root.

$2^{2} = 4$ $2^2=4$

$2 x - 3 = 4$ $2x-3=4$

Solve for $x :$ $x:$

$2xcancel(-3+3)=4+3$

$2x=7$

$x=7/2$