How do you solve $(2x+3)^(3/4) - 3 = 5$ ?

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Answer 1 · 2015-04-11T20:37:22

$(2x+3)^(3/4)-3 = 5$

is equivalent to
$(2x+3)^(3/4) = 8$

(take the cube root of both sides:)
$(2x+3)^(1/4) = 2$

(take both sides to the power of 4:)
$2x+3 = 16$

(simplify:)
$2x = 13$

$x= 6 1/2$

How do you solve (2x+3)^(3/4) - 3 = 5(2x+3)^(3/4) - 3 = 5?