How do you solve $2 x - 3 x = 11$ $2x-3x=11$ ?

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Answer 1 · 2018-03-09T15:34:47

$x = - 11$ $x = -11$

$2 x - 3 x = - 1 x$ $2x-3x=-1x$

So

$- 1 x = 11$ $-1x = 11$

Divide by $- 1$ $-1$ on both sides

$x = - 11$ $x = -11$

Answer 2 · 2018-03-09T15:35:55

$x = - 11$ $x=-11$

1) Subtract $3 x$ $3x$ from $2 x$ $2x$ :

$2 x - 3 x = 11$ $2x-3x=11$

$- x = 11$ $-x=11$

This can be rewritten as:

$(- 1) (x) = 11$ $(-1)(x)=11$

2) Multiply both sides by $- 1$ $-1$ , to change the L.H.S to $x$ $x$ :

$- 1 \cdot - 1 (x) = - 1 (11)$ $-1*-1(x)=-1(11)$

$\Rightarrow 1 (x) = - 11$ $=> 1(x)=-11$

$\Rightarrow x = - 11$ $=>x=-11$

Thus, solved.

How do you solve 2x−3x=112x-3x=11?