How do you solve $2x+4y=-1$ and $4x-3y=-2$ ?

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How do you solve $2x+4y=-1$ and $4x-3y=-2$ ?

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Answer 1 · 2016-04-22T16:25:09

The solution for the system of equations is:
$color(green)(x = - 1/2$
$color(green)(y =0$

Explanation:

$2x + 4y = -1$ , multiplying by $2$
$color(blue)(4x) + 8y = -2$ ................equation $(1)$

$color(blue)(4x) - 3y = -2$ .................equation $(2)$

Solving by elimination:

Subtracting equation $2$ from $1$ :
$cancelcolor(blue)(4x) + 8y = -2$

$-cancelcolor(blue)(4x) + 3y = +2$

$11 y = 0$

$y = 0/11$

$color(green)(y =0$

Finding $x$ from the first equation.

$2x + 4y = -1$

$2x = -1 - 4y$

$2x = -1 - 4 * 0$

$2x = -1$

$color(green)(x = - 1/2$

Answer 2 · 2016-04-22T16:25:16

The solution for the system of equations is:
$color(green)(x = - 1/2$
$color(green)(y =0$

Explanation:

$2x + 4y = -1$ , multiplying by $2$
$color(blue)(4x) + 8y = -2$ ................equation $(1)$

$color(blue)(4x) - 3y = -2$ .................equation $(2)$

Solving by elimination:

Subtracting equation $2$ from $1$ :
$cancelcolor(blue)(4x) + 8y = -2$

$-cancelcolor(blue)(4x) + 3y = +2$

$11 y = 0$

$y = 0/11$

$color(green)(y =0$

Finding $x$ from the first equation.

$2x + 4y = -1$

$2x = -1 - 4y$

$2x = -1 - 4 * 0$

$2x = -1$

$color(green)(x = - 1/2$

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How do you solve $2x+4y=-1$ and $4x-3y=-2$ ?

2 Answers

Explanation:

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How do you solve $2x+4y=-1$ and $4x-3y=-2$ ?