How do you solve $(2x-5)/4-x/3=2-(x+4)/6$ ?

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Answer 1 · 2017-03-19T18:36:11

$"answer : "x=31/4$

$(2x-5)/4-x/3=2-(x+4)/6$

$color(red)(3/3)*(2x-5)/4-color(blue)(4/4)*x/3=color(green)(12/12)*2-color(cyan)(2/2) (x+4)/6$

$(3(2x-5))/12-(4x)/12=24/12-(2(x+4))/12$

$(3(2x-5)-4x)/12=(24-2(x+4))/12$

$(3(2x-5)-4x)/cancel(12)=(24-2(x+4))/cancel(12)$

$3(2x-5)-4x=24-2(x+4)$

$cancel(6x)-15-cancel(4x)=24-2x-8$

$2x-15=16-2x$

$2x+2x=16+15$

$4x=31$

$(cancel(4)x)/cancel(4)=31/4$

$x=31/4$

How do you solve (2x-5)/4-x/3=2-(x+4)/6(2x-5)/4-x/3=2-(x+4)/6?