How do you solve $(2x)/9 + 1/3 = 5$ ?

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Answer 1 · 2016-05-08T19:29:51

Get rid of the fractions first, then solve for the unknown.

$x = 21$

Whenever an equation has fractions, it is possible to get rid of them by multiplying each term by the LCM of the denominators.

$(2x)/9 + 1/3 = 5 " " xx9$

$color(red)9xx(2x)/9 + color(red)9xx1/3 = color(red)9xx5$

$cancel9xx(2x)/cancel9 + cancel9^3xx1/cancel3 = 9xx5$

$2x + 3 = 45$

$2x = 45-3$

$2x = 42$

$x = 21$

How do you solve (2x)/9 + 1/3 = 5(2x)/9 + 1/3 = 5?