How do you solve (2x)/(x-3)=(3x)/(x^2-9)+2? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer maganbhai P. Mar 14, 2018 x=-6 Explanation: (2x)/(x-3)=(3x)/(x^2-9)+2 =>(2x)/(x-3)=(3x)/((x-3)(x+3))+2/1 =>((2x)(x+3))/((x-3)(x+3))=(3x(1))/((x-3)(x+3))+(2(x-3)(x+3))/((x-3)(x+3) =>2x(x+3)=3x+2(x^2-9) =>cancel(2x^2)+6x=3x+cancel(2x^2)-18 =>6x=3x-18 =>3x=-18=>x=-6 Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve 5x-\frac{1}{x}=4? How do you solve -3 + \frac{1}{x+1}=\frac{2}{x} by finding the least common multiple? What is the least common multiple for \frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6} and how do... How do you solve \frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}? How do you solve by clearing the denominator of 3/x+2/x^2=4? How do you solve 2/(x^2+2x+1)-3/(x+1)=4? How do you solve equations with rational expressions 1/x+2/x=10? How do you solve for y in (y+5)/ 2 - y/3 =1? See all questions in Clearing Denominators in Rational Equations Impact of this question 2593 views around the world You can reuse this answer Creative Commons License