How do you solve $(2x)/(x+3)=(3x)/(x-3)$ ?

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Answer 1 · 2018-05-07T09:56:25

$x = 0 or x=-15$

${2x}/{x+3} = {3x}/{x-3}$

$2x(x-3) = 3x(x+3)$

$2x(x-3) - 3x(x+3) = 0$

$x(2x -6 - 3x - 9) = 0$

$x(-x-15) = 0$

$x = 0 or x=-15$

Check:

${2(0)}/(0+3)=0$

${3(0)}/(0-3) = 0 quad sqrt$

${2(-15)}/(-15+3) = {-30}/{-12}=5/2$

${3(-15)}/(-15-3)=45/18 = 5/2 quad sqrt$

How do you solve (2x)/(x+3)=(3x)/(x-3)(2x)/(x+3)=(3x)/(x-3)?