How do you solve $\frac{3}{4} (x + 2) = - 1$ $3/4(x+2)=-1$ ?

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Answer 1 · 2016-02-15T21:51:56

$x = - \frac{10}{3}$ $x=-10/3$

$\frac{3}{4} (x + 2) = - 1$ $3/4(x+2)=-1$

Multiply both sides by $4$ $4$ .

$(4) \frac{3}{4} (x + 2) = - 1 \times 4$ $(4)3/4(x+2)=-1xx4$

Simplify.

$(cancel 4)(3/cancel 4)(x+2)=-4$

Simplify.

$3(x+2)=-4$

Expand the left side.

$3x+6=-4$

Subtract $6$ from both sides.

$3x=-4-6$

Simplify.

$3x=-10$

Divide both sides by $3$ .

$x=-10/3$

How do you solve 3/4(x+2)=-134(x+2)=−13/4(x+2)=-1?