How do you solve #3/4x-2/3=5/6#?

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Answer 1 · 2016-07-28T13:29:46

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To make this easier on ourselves, let's give a common denominator to all of the fractions first:

#9/12x-8/12=10/12#

Next, let's get rid of those fractions by multiplying each side of the equation by 12:

#12(9/12x-8/12)=(10/12)12#

#9x-8=10#

From here, it's easy. Add 8 to each side to isolate the variable:

#9x=18#

And divide to each side by 9:

#x=2#