How do you solve #3/(8x)-1/(3x+6)=1/(6x)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Konstantinos Michailidis Sep 30, 2015 Refer to explanation Explanation: It is #3/(8x)-1/(3x+6)=1/(6x)=>3/(8x)-1/(6x)=1/(3x+6)=> (3*6x-8x)/(48x^2)=1/(3x+6)=>(10x)/(48x^2)=1/(3x+6)=> 5/(24x)=1/(3x+6)=>5(3x+6)=24x=>15x+30=24x=> 9x=30=>x=10/3# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1651 views around the world You can reuse this answer Creative Commons License