How do you solve $3/(x+3) - 4/(x-3) = (5x)/(x^2-9)$ ?

Question

6789 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-03T01:45:52

$x=-7/2$

$3/(x+3) - 4/(x-3) = (5x)/(x^2-9)$

$(3(x-3)-4(x+3))/(x^2-9) = (5x)/(x^2-9)$

For $x!= +-3$ :
$(3(x-3)-4(x+3))/cancel(x^2-9) = (5x)/cancel(x^2-9)$

$3(x-3)-4(x+3) = 5x$

$3x-9-4x-12 = 5x$

$-6x=21$

$x=-7/2$

How do you solve 3/(x+3) - 4/(x-3) = (5x)/(x^2-9)3/(x+3) - 4/(x-3) = (5x)/(x^2-9)?