How do you solve $3/(x-3)=x/(x-3)-3/2$ ?

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Answer 1 · 2018-03-03T13:56:13

No solutions for $x$

First subtract $3/(x-3)$ from both sides:

$0 = x/(x-3) - 3/(x-3) -3/2$

Simplifying:

$0 = (x-3)/(x-3) - 3/2$

We can cancel, the $(x-3)$ as it is on both bottom and top

$0 = cancel((x-3))/cancel((x-3)) - 3/2$

$=> 0 = 1-3/2$

$=> 0 = -1/2$

But we know this is not true, so hence there are no solutions to this problem!

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