Question

How do you solve `3/x+x=4`?

Answer 1

`x=1" or "x=3`

Explanation:

`"multiply all terms by "x`

`cancel(x)xx3/cancel(x)+x^2=4x`

`rArr3+x^2=4x`

`"subtract "4x" from both sides"`

`rArrx^2-4x+3=0larrcolor(blue)"in standard form"`

`"the factors of + 3 which sum to - 4 are - 1 and - 3"`

`rArr(x-1)(x-3)=0`

`"equate each factor to zero and solve for x"`

`x-1=0rArrx=1`

`x-3=0rArrx=3`