How do you solve $3/(z+7)=2/(z-4)$ ?

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Answer 1 · 2016-03-17T14:28:30

$z=26$

$color(blue)(3/(z+7)=2/(z-4)$

Cross multiply $color(brown)(a/b=c/d,ad=bc$

$rarr3(z-4)=2(z+7)$

Use distributive property $color(brown)(a(b+c)=ab+ac$

$rarr3z-12=2z+14$

$rarr3z-2z=14+12$

$rarrz=14+12$

$color(green)(rArrz=26$

Check

$color(indigo)(3/(26+7)=2/(26-4)$

$color(indigo)(3/33=2/22$

$color(indigo)(1/11=1/11$

How do you solve 3/(z+7)=2/(z-4)3/(z+7)=2/(z-4)?