How do you solve 30< 5x \leq 40?

1 Answer
Jan 26, 2017

See the entire solution process below:

Explanation:

To solve this divide each portion of the system of inequalities by color(red)(5) to solve for x while keeping the system of inequalities balanced:

30/color(red)(5) < (5x)/color(red)(5) <= 40/color(red)(5)

6 < (color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) <= 8

6 < x <= 8