How do you solve $3q+11=-1$ ?

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Answer 1 · 2016-07-27T02:04:26

$color(purple)("q= - 4")$

$color(coral)("Subtract 11 on both sides:")$

$3q+cancel11= -1$
$color(white)(aa) -cancel11 -11$

11 cancels out on the left side, and when you subtract 11 from -1 on the right side you obtain -12:

$3q=-12$

$color(green)("Divide both sides 3 to get q by itself.")$

$(cancel"3"q)/cancel3=(-12)/3$

Now you are just left with $q$ on the left side and -4 on the right side.

Thus,
$color(red)"q = - 4"$

How do you solve 3q+11=-13q+11=-1?