Question

How do you solve `3sqrt(2x)=4` and find any extraneous solutions?

Answer 1

See below.

Explanation:

`3sqrt(2x)=4`

`sqrt(2x)=4/3`

`2x=16/9`

`x=8/9`

There will be extraneous solutions ONLY if the equation equals a negative number, or if the number inside the radical is imaginary. Since this does not describe our equation, there are no extraneous solutions.