How do you solve $3sqrt(4y)=6$ ?

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Answer 1 · 2015-04-17T14:11:20

Take $3$ to the right:
$sqrt(4y)=6/3$
$sqrt(4y)=2$
square both sides and solve for $y$

Answer 2 · 2015-04-17T15:51:54

Know that:

$sqrt(ab)=sqrt(a)sqrt(b)$

So:

$3sqrt(4y)=6$

$(3sqrt(4y))/3=6/3$

$sqrt(4y)=2$

$sqrt(4)sqrt(y)=2$

$(sqrt(4)sqrt(y))/sqrt(4)=2/(sqrt(4))$

$sqrt(y)=1$

$y=1^2$

$:.y=1$

How do you solve 3sqrt(4y)=63sqrt(4y)=6?