How do you solve 3sqrtx + x = 10?

1 Answer
Jun 24, 2016

x=4

Explanation:

'Transpose' x to the other side of the equation and square both sides.
Expand the binomial on the right side.
'Transpose 9x to the right side of the equation.
Use the quadratic formula.

It should look like this:

3sqrtx=10-x

9x=(10-x)^2

9x=100-20x+x^2

0=100-29x+x^2

x=-25

and

x=4

However, we will not accept x=-25 as an answer because it will yield an imaginary number in the original equation. The squaring step (step1b) created this extra root.