How do you solve $3 \frac{x}{2} - 4 = 5$ $3x/2-4=5$ ?

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How do you solve $3 \frac{x}{2} - 4 = 5$ $3x/2-4=5$ ?

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Answer 1 · 2018-06-21T06:31:48

Write as $(\frac{3}{2}) x - 4 = 5$ $(3/2)x-4=5$
$x = 6$ $x=6$

Explanation:

Add 4 to both sides $(\frac{3}{2}) x = 9$ $(3/2)x=9$
Multiply both sides by the reciprocal of $(\frac{3}{2})$ $(3/2)$
$(\frac{2}{3}) (\frac{3}{2}) x = (\frac{9}{1}) (\frac{2}{3})$ $(2/3)(3/2)x=(9/1)(2/3)$
Cancel the common factor of 3
$x = (\frac{3}{1}) (\frac{2}{1}) = 6$ $x=(3/1)(2/1)=6$

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How do you solve $3 \frac{x}{2} - 4 = 5$ $3x/2-4=5$ ?

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