How do you solve $3x^2 + 5x + 1 = 0$ using the quadratic formula?

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Answer 1 · 2018-08-04T06:46:53

$x = (-5 + sqrt13)/6$ and $x = (-5 - sqrt13)/6$

$3x^2 + 5x + 1 = 0$

The quadratic formula is $x = (-b +- sqrt(b^2 - 4ac))/(2a)$ .

We know that:
$a = 3$ , $b = 5$ , and $c = 1$ based on the equation, so let's plug them into the formula:

$x = (-5 +- sqrt(5^2 - 4(3)(1)))/(2(3))$

$x = (-5 +- sqrt(25 - 12))/6$

$x = (-5 +- sqrt13)/6$

Hope this helps!

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