How do you solve $3 x - 2 y = 4$ $3x - 2y = 4$ and $y = 2 x - 6$ $y = 2x - 6$ ?

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Answer 1 · 2015-08-04T05:54:02

The solution for the system of equations is
$x = 8, y = 10$ $color(blue)(x=8,y=10$

$3 x - 2 y = 4$ $3x−2y=4$ .....equation $(1)$ $(1)$
$y = 2 x - 6$ $y=color(blue)(2x−6$ .......equation $(2)$ $(2)$

Solving through substitution

Substituting equation $(2)$ $(2)$ in equation $(1)$ $(1)$
$3 x - 2 \cdot (2 x - 6) = 4$ $3x−2*(color(blue)(2x−6))=4$

$3 x - 4 x + 12 = 4$ $3x−4x +12=4$

$- x + 12 = 4$ $-x +12=4$
$x = 8$ $color(blue)(x=8$

Finding $y$ $y$ by substituting $x$ $x$ in equation $2$ $2$
$y = 2 x - 6$ $y=2x−6$

$y = 2 \cdot 8 - 6$ $y=2*8−6$

$y = 16 - 6$ $y=16−6$

$y = 10$ $color(blue)(y=10$

How do you solve 3x - 2y = 43x−2y=43x - 2y = 4 and y = 2x - 6y=2x−6y = 2x - 6?